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Here is how the program works In the XYCoord class, the only constructor that actually initializes the x and y fields is XYCoord(int, int) The other two constructors simply invoke XYCoord(int, int) through this For example, when object t1 is created, its constructor, XYCoord( ), is called This causes this(0, 0) to be executed, which in this case translates into a call to XYCoord(0, 0) The creation of t2 works in similar fashion

8:

10-15

One reason why invoking overloaded constructors through this can be useful is that it can prevent the unnecessary duplication of code In the foregoing example, there is no reason for all three constructors to duplicate the same initialization sequence, which the use of this avoids Another advantage is that you can create constructors with implied default arguments that are used when these arguments are not explicitly specified For example, you could create another XYCoord constructor as shown here:

public XYCoord(int x) : this(x, x) { }

This constructor automatically defaults the y coordinate to the same value as the x coordinate Of course, it is wise to use such default arguments carefully because their misuse could easily confuse users of your classes

University of Maryland (MArch) School of Architecture College Park, MD 20742 archumdedu/

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C# 30 added a new feature called object initializers that provides another way to create an object and initialize its fields and properties (See 10 for a discussion of properties) Using object initializers, you do not call a class constructor in the normal way Rather, you specify the names of the fields and/or properties to be initialized, giving each an initial value Thus, the object initializer syntax provides an alternative to explicitly invoking a class constructor The primary use of the object initializer syntax is with anonymous types created in a LINQ expression (Anonymous types and LINQ are described in 19) However, because the object initializers can be used (and occasionally are used) with a named class, the fundamentals of object initialization are introduced here Let s begin with a simple example:

// A simple demonstration that uses object initializers using System; class MyClass { public int Count; public string Str; } class ObjInitDemo { static void Main() { // Construct a MyClass object by using object initializers MyClass obj = new MyClass { Count = 100, Str = "Testing" }; ConsoleWriteLine(objCount + " " + objStr); } }

This produces the following output:

Clearly, the computation of a circle s area could not be satisfactorily achieved without the use of floating-point data

Inside a method, execution proceeds from one statement to the next, top to bottom It is possible to alter this flow through the use of the various program control statements supported by C# Although we will look closely at control statements later, two are briefly introduced here because we will be using them to write sample programs

j xexdx = xex - e x = ex(x - I)

2:

An Overview of C#

You can selectively execute part of a program through the use of C# s conditional statement: the if The if statement works in C# much like the IF statement in any other language For example, it is syntactically identical to the if statements in C, C++, and Java Its simplest form is shown here: if(condition) statement; Here, condition is a Boolean (that is, true or false) expression If condition is true, then the statement is executed If condition is false, then the statement is bypassed Here is an example:

if(10 < 11) ConsoleWriteLine("10 is less than 11");

In this case, since 10 is less than 11, the conditional expression is true, and WriteLine( ) will execute However, consider the following:

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if(10 < 9) ConsoleWriteLine("this won t be displayed");

In this case, 10 is not less than 9 Thus, the call to WriteLine( ) will not take place C# defines a full complement of relational operators that can be used in a conditional expression They are shown here:

Operator < <= > >= == != Meaning Less than Less than or equal to Greater than Greater than or equal to Equal to Not equal

The lxe*drx can itself be integrated by parts as was done in the previous problem Use the result of problem 10-16 to write

Here is a program that illustrates the if statement:

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